In an FCC lattice, what is the contribution from corner atoms and face-centered atoms?

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Multiple Choice

In an FCC lattice, what is the contribution from corner atoms and face-centered atoms?

Explanation:
The key idea is how atoms are shared between unit cells in a crystalline lattice. In an FCC lattice, atoms at corners are shared by eight unit cells, so each corner atom contributes 1/8 to a given unit cell. Atoms on the faces are shared by two unit cells, so each face-centered atom contributes 1/2 to a given unit cell. There are eight corners, giving 8×1/8 = 1, and six face centers, giving 6×1/2 = 3, for a total of 4 atoms per unit cell. So the contributions are 1/8 from each corner position and 1/2 from each face-centered position.

The key idea is how atoms are shared between unit cells in a crystalline lattice. In an FCC lattice, atoms at corners are shared by eight unit cells, so each corner atom contributes 1/8 to a given unit cell. Atoms on the faces are shared by two unit cells, so each face-centered atom contributes 1/2 to a given unit cell. There are eight corners, giving 8×1/8 = 1, and six face centers, giving 6×1/2 = 3, for a total of 4 atoms per unit cell. So the contributions are 1/8 from each corner position and 1/2 from each face-centered position.

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